128m^2-18=0

Solution for 128m^2-18=0 equation:

128m^2-18=0

a = 128; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·128·(-18)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*128}=\frac{-96}{256}
=-3/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*128}=\frac{96}{256}
=3/8
$